If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5k^2+4k=12
We move all terms to the left:
5k^2+4k-(12)=0
a = 5; b = 4; c = -12;
Δ = b2-4ac
Δ = 42-4·5·(-12)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-16}{2*5}=\frac{-20}{10} =-2 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+16}{2*5}=\frac{12}{10} =1+1/5 $
| 5k^2+4k-12=0 | | 8x2=83+10 | | 3x^2+7x-2050=0 | | 7x+6x-4x=38+7 | | 4x=-5x+27 | | -40=5w | | 3x^2+7x+2050=0 | | 51-x=25 | | 4x+19=8x-14 | | 5x+6=1x+30 | | 2(9.5+-1.5y)+3y=19 | | 16x-2=8x+2 | | 2x+8=29 | | 160=8(8-3x) | | 86=2(1-7n) | | 1,2+0,8•(5x-3)-(2-x)=0 | | -2-8(6k-2)=-274 | | 5(x-4)+2=-8 | | 5x+6=4x+18 | | 3x-8=7–2x | | 317=4a+5(1+7a) | | x+(.04*x)+3=0 | | 62x=61-3x | | x+(.04*x)=0 | | 4(a+7)=41 | | 5.6=-10+x | | Z+4/z+1=3 | | 5x2+11x−12=0 | | 1/5=c=4/5 | | Z+(4/z+1)=3 | | 5x-17=2x-8 | | 10x=-8+8x |